: Divide the current by factors for temperature and grouping (e.g.,

$$I_t \geq \frac1250.96 \times 0.79 \times 1.0$$

Decision: Since 137 A < 164.8 A, the 35 mm² is too small. (Capacity 176 A).

$$I_t \geq \fracI_nC_a \times C_g \times C_i$$

I=P3×V×pfcap I equals the fraction with numerator cap P and denominator the square root of 3 end-root cross cap V cross pf end-fraction = Power in Watts = Power factor 2. Cross-Sectional Area ( ) for Voltage Drop To ensure the voltage drop ( ΔVcap delta cap V